Spiceland Township
Location in Henry County
Location in Henry County
Coordinates: 39°49′12″N 85°27′12″W / 39.82000°N 85.45333°W / 39.82000; -85.45333
CountryUnited States
StateIndiana
CountyHenry
Government
  TypeIndiana township
Area
  Total22.32 sq mi (57.8 km2)
  Land22.22 sq mi (57.5 km2)
  Water0.09 sq mi (0.2 km2)  0.40%
Elevation
1,040 ft (317 m)
Population
 (2010)
  Total2,279
  Density102.5/sq mi (39.6/km2)
GNIS feature ID0453862

Spiceland Township is one of thirteen townships in Henry County, Indiana, United States. As of the 2010 census, its population was 2,279 and it contained 991 housing units.[1]

Spiceland Township was organized in 1842.[2] It was named from the growth of spice bushes within its borders.[2]

Geography

According to the 2010 census, the township has a total area of 22.32 square miles (57.8 km2), of which 22.22 square miles (57.5 km2) (or 99.55%) is land and 0.09 square miles (0.23 km2) (or 0.40%) is water.[1]

Cities and towns

Unincorporated towns

(This list is based on USGS data and may include former settlements.)

Adjacent townships

Major highways

Education

Spiceland Township residents are served by the Spiceland Town-Township Public Library.[3]

References

  1. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
  2. 1 2 Hazzard, George (1906). Hazzard's History of Henry County, Indiana, 1822-1906. G. Hazzard, author and publisher. p. 964.
  3. "Indiana public library directory" (PDF). Indiana State Library. Retrieved March 7, 2018.
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