Semenov-Tian-Shansky Peak | |
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Pik Semonova-Tyan'shanskogo, Alamedin Peak | |
Highest point | |
Elevation | 4,895 m (16,060 ft) |
Prominence | 2,231 m (7,320 ft) |
Isolation | 233.57 km (145.13 mi) |
Coordinates | 42°31′16″N 74°34′18″E / 42.52111°N 74.57167°E |
Geography | |
Semenov-Tian-Shansky Peak | |
Parent range | Kyrgyz Ala-Too Range, Tian Shan |
Semenov-Tian-Shansky Peak (Russian: Пик Семёнова-Тяньшанского, romanized: Pik Semonova-Tyan'shanskogo, Kyrgyz: Аламүдүн чокусу, romanized: Alamüdün çokusu, lit. 'Alamedin Peak') is a mountain in the Kyrgyz Ala-Too Range of the Tian Shan. It is located in Ala Archa National Park in Kyrgyzstan. It is the tallest mountain in the Kyrgyz Ala-Too Range and is an Ultra with a prominence of 2231m.[1]
The mountain is situated between the Ala-Archa River to the west and the Alamedin River to the east.
History
The peak is named for the Russian geographer Peter Semenov-Tian-Shansky.
References
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