Hobart Township
Coordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W / 41.54667; -87.26472
CountryUnited States
StateIndiana
CountyLake
Government
  TypeIndiana township
Area
  Total25.98 sq mi (67.3 km2)
  Land25.47 sq mi (66.0 km2)
  Water0.51 sq mi (1.3 km2)
Elevation627 ft (191 m)
Population
 (2010)
  Total39,417
  Density1,547.4/sq mi (597.5/km2)
FIPS code18-34132[2]
GNIS feature ID453414

Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[3]

Geography

According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water.[3]

References

  1. "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  3. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.


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