Doubles
2019 Lale Cup
Champions	Marie Bouzková Rosalie van der Hoek
Runners-up	Ilona Kremen Iryna Shymanovich
Score	7–5, 6–7(2–7), [10–5]

Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.

Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7^(2–7), [10–5].^[1]

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	O Doroshina P Monova
		Ç Büyükakçay A Vrljić	w/o						Ç Büyükakçay A Vrljić
		G Poznikhirenko S Sharipova	7	4	[8]				M Bouzková R van der Hoek	w/o
		M Bouzková R van der Hoek	5	6	[10]											M Bouzková R van der Hoek	7	7
	3	B Cengiz J Rompies	6	6											3	B Cengiz J Rompies	5	5
	WC	Z Erman Z Sönmez	3	4				3	B Cengiz J Rompies	1	6	[11]
		İ Soylu B Štefková	6	6					İ Soylu B Štefková	6	4	[9]
	WC	İ Öz M Sezer	3	3																			M Bouzková R van der Hoek	7	62	[10]
		I Kremen I Shymanovich	6	6																			I Kremen I Shymanovich	5	77	[5]
		Á Bukta V Juhászová	2	3					I Kremen I Shymanovich	4	6	[11]
		G Minnen P Özgen	7	6					G Minnen P Özgen	6	3	[9]
	4	V Grammatikopoulou A Raina	5	4												I Kremen I Shymanovich	66	6	[11]
		A Gasanova J Terziyska	6	77											2	R Șerban I Shinikova	78	3	[9]
		F Al-Nabhani C Anıl	1	63					A Gasanova J Terziyska	6	62	[7]
	WC	L Aiche BE Gümüşsoy	0	0				2	R Șerban I Shinikova	4	77	[10]
	2	R Șerban I Shinikova	6	6

References

• Main Draw