1918 Iowa gubernatorial election

November 5, 1918
 
Nominee William L. Harding Claude R. Porter
Party Republican Democratic
Popular vote 192,662 178,815
Percentage 50.55% 46.92%

Governor before election

William L. Harding
Republican

Elected Governor

William L. Harding
Republican

The 1918 Iowa gubernatorial election was held on November 5, 1918. Republican nominee William L. Harding defeated Democratic nominee Claude R. Porter with 50.55% of the vote.

General election

Candidates

Major party candidates

  • William L. Harding, Republican
  • Claude R. Porter, Democratic

Other candidates

  • Andrew Engle, Socialist
  • M. L. Christian, Prohibition

Results

1918 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William L. Harding (incumbent) 192,662 50.55%
Democratic Claude R. Porter 178,815 46.92%
Socialist Andrew Engle 8,005 2.10%
Prohibition M. L. Christian 1,625 0.43%
Majority 13,847
Turnout
Republican hold Swing

References

  1. Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 1, 2020.
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