As a stellation

The stellation of a polyhedron extends the faces of a polyhedron into infinite planes and generates a new polyhedron that is bounded by these planes as faces and the intersections of these planes as edges. The Fifty Nine Icosahedra enumerates the stellations of the regular icosahedron, according to a set of rules put forward by J. C. P. Miller, including the complete stellation. The Du Val symbol of the complete stellation is H, because it includes all cells in the stellation diagram up to and including the outermost "h" layer.^[5]

As a simple polyhedron

A polyhedral model can be constructed by 12 sets of faces, each folded into a group of five pyramids.

As a simple, visible surface polyhedron, the outward form of the final stellation is composed of 180 triangular faces, which are the outermost triangular regions in the stellation diagram. These join along 270 edges, which in turn meet at 92 vertices, with an Euler characteristic of 2.^[8]

The 92 vertices lie on the surfaces of three concentric spheres. The innermost group of 20 vertices form the vertices of a regular dodecahedron; the next layer of 12 form the vertices of a regular icosahedron; and the outer layer of 60 form the vertices of a nonuniform truncated icosahedron. The radii of these spheres are in the ratio^[9]

$${\displaystyle {\sqrt {{\frac {3}{2}}\left(3+{\sqrt {5}}\right)}}\,:\,{\sqrt {{\frac {1}{2}}\left(25+11{\sqrt {5}}\right)}}\,:\,{\sqrt {{\frac {1}{2}}\left(97+43{\sqrt {5}}\right)}}\,.}$$

Convex hulls of each sphere of vertices

Inner	Middle	Outer	All three
20 vertices	12 vertices	60 vertices	92 vertices
Dodecahedron	Icosahedron	Nonuniform truncated icosahedron	Complete icosahedron

When regarded as a three-dimensional solid object with edge lengths ${\displaystyle a}$, ${\displaystyle \varphi a}$, ${\displaystyle \varphi ^{2}a}$ and ${\displaystyle \varphi ^{2}a{\sqrt {2}}}$ (where ${\displaystyle \varphi }$ is the golden ratio) the complete icosahedron has surface area^[9]

$${\displaystyle S={\frac {1}{20}}(13211+{\sqrt {174306161}})a^{2}\,,}$$

and volume^[9]

$${\displaystyle V=(210+90{\sqrt {5}})a^{3}\,.}$$

As a star polyhedron

Twenty 9/4 polygon faces (one face is drawn yellow with 9 vertices labeled.)

2-isogonal 9/4 faces

The complete stellation can also be seen as a self-intersecting star polyhedron having 20 faces corresponding to the 20 faces of the underlying icosahedron. Each face is an irregular 9/4 star polygon, or enneagram.^[5] Since three faces meet at each vertex it has 20 × 9 / 3 = 60 vertices (these are the outermost layer of visible vertices and form the tips of the "spines") and 20 × 9 / 2 = 90 edges (each edge of the star polyhedron includes and connects two of the 180 visible edges).

When regarded as a star icosahedron, the complete stellation is a noble polyhedron, because it is both isohedral (face-transitive) and isogonal (vertex-transitive).