Doubles
2004 BCR Open Romania
Champions	Lucas Arnold Ker Mariano Hood
Runners-up	José Acasuso Óscar Hernández
Score	7–6(7–5), 6–1
Draw	16 (2WC/1Alt)
Seeds	4

Karsten Braasch and Sargis Sargsian were the defending champions, but Sargsian did not compete this year. Braasch teamed up with Philipp Kohlschreiber and lost in the semifinals to José Acasuso and Óscar Hernández.^[1]

Lucas Arnold Ker and Mariano Hood won the title by defeating Acasuso and Hernández 7–6^(7–5), 6–1 in the final.^[2]

Seeds

Draw

Draw

	First round							Quarterfinals							Semifinals							Final
	1	J Knowle N Zimonjić	4	4
		I Andreev N Davydenko	6	6					I Andreev N Davydenko
		J Acasuso Ó Hernández	7	77					J Acasuso Ó Hernández	w/o
		D Ferrer Á López Morón	5	62												J Acasuso Ó Hernández	65	6	6
	3	Y Allegro M Kohlmann	6	3	6											K Braasch P Kohlschreiber	77	2	3
		A Martín D Sánchez	3	6	4			3	Y Allegro M Kohlmann	3	62
	WC	F Mergea H Tecău	6	4	5				K Braasch P Kohlschreiber	6	77
		K Braasch P Kohlschreiber	2	6	7																		J Acasuso Ó Hernández	65	1
		P Pála D Škoch	3	77	6																	2	L Arnold Ker M Hood	77	6
		F Mayer R Wassen	6	64	0				P Pála D Škoch	5	4
		M Fyrstenberg M Matkowski	6	6					M Fyrstenberg M Matkowski	7	6
	Alt	R Sluiter D van Scheppingen	3	3												M Fyrstenberg M Matkowski	1	3
	WC	G Moraru G Trifu	0	2											2	L Arnold Ker M Hood	6	6
		D Bracciali G Galimberti	6	6					D Bracciali G Galimberti	4	6	3
		M Bertolini T Vanhoudt	3	2				2	L Arnold Ker M Hood	6	4	6
	2	L Arnold Ker M Hood	6	6

References

External links

• Main draw (ATP)
• ITF tournament profile