1838 Rhode Island gubernatorial election

April 18, 1838
 
Nominee William Sprague John Brown Francis
Party Whig Democratic
Popular vote 3,984 3,504
Percentage 52.51% 46.18%

Governor before election

John Brown Francis
Democratic

Elected Governor

William Sprague
Whig

The 1838 Rhode Island gubernatorial election was held on April 18, 1838.[1][2]

Incumbent Democratic Governor John Brown Francis ran for election to a sixth term but was defeated by Whig nominee William Sprague.

General election

Candidates

Results

1838 Rhode Island gubernatorial election[3][4][5][6][7][8][9]
Party Candidate Votes % ±%
Whig William Sprague 3,984 52.51%
Democratic John Brown Francis (incumbent) 3,504 46.18%
Scattering 99 1.30%
Majority 480 6.33%
Turnout 7,587
Whig gain from Democratic Swing

References

  1. "The Election". Herald of the times. Newport, R.I. March 29, 1838. p. 2. Retrieved October 19, 2021.
  2. "The Elections". Richmond enquirer. Richmond, Va. April 7, 1838. p. 2. Retrieved October 19, 2021.
  3. "RI Governor, 1838". Our Campaigns. Retrieved October 19, 2021.
  4. Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. p. 76. ISBN 1-56802-396-0.
  5. Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. p. 235. ISBN 978-0-7864-1439-0.
  6. Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 270–271. ISBN 0-930466-17-9.
  7. Kallenbach, Joseph E.; Kallenbach, Jessamine S., eds. (1977). American State Governors, 1776-1976. Vol. I. Dobbs Ferry, N.Y.: Oceana Publications, Inc. p. 512. ISBN 0-379-00665-0.
  8. Manual with Rules and Orders for the Use of the General Assembly of the State of Rhode Island, 1888-89. Providence: E. L. Freeman & Co., Printers to the State. 1888. p. 101.
  9. "Rhode-Island Legislature". The Rhode-Island Republican. Newport, R.I. May 9, 1838. p. 2. Retrieved October 19, 2021.
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